Fisiologiahumanatresguerres4taedicionpdf100 A: You are calling a method on a value that has not been set. Your sql string appears to be concatenating a populated string (HttpResponse.ContentLength) to the string retrieved. The evaluation of HttpResponse.ContentLength is done before you even have a value to bind to. Check to see if your if statement is being executed before the assignment has been completed. My guess is that this is what is happening: HttpResponse response = new HttpResponse(String.Format(@"{0}/Download/{1}", Config.SiteRoot.ToString(), FileName), HttpContext.Current.Response); HttpContext.Current.Response.Clear(); HttpContext.Current.Response.WriteFile(FilePath); HttpContext.Current.Response.Close(); HttpContext.Current.Response.End(); This is the snippet that might be called before you set the HttpResponse. A: Try not to assign values to the HttpContext.Response object. You probably meant to just use the FilePath variable. Q: Evaluating $\lim_{n\to \infty}\sum_{k=1}^n \sqrt{\frac{k}{n^2+k}}$ I came across this problem as a practice exam, with the following: $$\lim_{n\to \infty} \sum_{k=1}^n \sqrt{\frac{k}{n^2+k}}$$ I have seen some answers for this type of question, but no one seems to get to the answer I gave. $$\sum_{k=1}^n \frac{k}{n(n+1)}$$ $$=\frac{1}{n(n+1)}\sum_{k=1}^n k$$ $$=\frac{1}{(n^2+n)(n+1)}$$ How do you get to the answer I gave? A: Your series is equal to $\frac{1}{n(n+1)}\sum_{k=1}^{n} k=\frac{1}{n^2+n}$, so for $n\rightarrow\infty$ the limit is $\frac{1}{2}$. Mold House 1cdb36666d
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